7(x+1)=4[x-(3-x)]

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Solution for 7(x+1)=4[x-(3-x)] equation:


Simplifying
7(x + 1) = 4[x + -1(3 + -1x)]

Reorder the terms:
7(1 + x) = 4[x + -1(3 + -1x)]
(1 * 7 + x * 7) = 4[x + -1(3 + -1x)]
(7 + 7x) = 4[x + -1(3 + -1x)]
7 + 7x = 4[x + (3 * -1 + -1x * -1)]
7 + 7x = 4[x + (-3 + 1x)]

Reorder the terms:
7 + 7x = 4[-3 + x + 1x]

Combine like terms: x + 1x = 2x
7 + 7x = 4[-3 + 2x]
7 + 7x = [-3 * 4 + 2x * 4]
7 + 7x = [-12 + 8x]

Solving
7 + 7x = -12 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
7 + 7x + -8x = -12 + 8x + -8x

Combine like terms: 7x + -8x = -1x
7 + -1x = -12 + 8x + -8x

Combine like terms: 8x + -8x = 0
7 + -1x = -12 + 0
7 + -1x = -12

Add '-7' to each side of the equation.
7 + -7 + -1x = -12 + -7

Combine like terms: 7 + -7 = 0
0 + -1x = -12 + -7
-1x = -12 + -7

Combine like terms: -12 + -7 = -19
-1x = -19

Divide each side by '-1'.
x = 19

Simplifying
x = 19

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